Let's get this conundrum clear now. How do they behave in various setups. Our basic assumption is that these three free electrons are in equilateral triangle shape so that the distance between any two electrons is the same.
Major update starts
Let's assume that the initial distance between the electrons is large enough for not disturbing the wave pattern generated by these electrons (at least not too much), so that second law is applicaple. Now we can describe quolitative what happens. After more detailed description of repulsive force we are able to do quantitative predictions regarding the timing and trajectories.
Electrons having parallel spinning vectors experience attractive force towards each other as stated by second law and they start moving towards the center of the system. FTE density between electrons ncreases to the point where electrons' trajectories are reversed. Build up repulsive potential energy does the job. If one of the electrons had antiparallel spinning vector orientation at begin with then things would progress differently. Now the electron with antiparallel spinning vector starts immediately generate repulsive force towards the other two. At the same time those two electrons with parallel spinning vectors attracts each other to the point where repulsion kicks in.
In principle it should be possible to measure the different electron behaviour between this setup and the setup where all spinning vectors were parallel. All we need to measure is if all these electrons hit symmetrically (and with proper distances) set up measuring devices at the same time. In case of all spinning vectors parallel, electrons should hit the measuring devices at the same time but in the other case one electron (antiparallel one) should hit the measuring device before the other two. Those other two electrons have to travel an additional distance before they start experience the repulsive force.
Major update ends (text below is wrong)
All spinning vectors are parallel. The key player is the bottom electron which has FTEP flux which ejects FTEPs from underneath itself towards the other two (for more information check out subsection Two Electron Based Particles from Introduction to Theory of Everything by Illusion). This electron (electron B) starts to change its spinning vector orientation after the other two. But which one of these other two electrons starts the spinning orientation changing? Again, the surrounding FTE density dictates the order. The one which is closer to Earth's center of mass (electron C) generates denser FTEP flux (*), hence will be the anchor for the other electron. So, the spinning vector changing order would be, top electron, down electron and the original anchor electron. This order is also the order for electrons leaving the scene.
(*) If the triangle is top down, then the upper electron which ejects FTEPs from underneath of itself towards the other upper electron will be the anchor for the other upper electron. In the picture right it would electron A.
There is two parallel spinning vectors (electrons A and B) and one antiparallel (electron C). This one is easy. Based on TL2 those antiparallel spinning vectors (B and C) generate repulsive force which triggers the movement for those electrons.
That single antiparallel electrons experiences the repulsion first and after that, electron A changes its spinning vector, which leads to repulsion between electrons A and B. At the same time electrons A and B are travelling away from electron C.
Again surrounding FTE ordered which electron changes its spinning vector orientation. Momentum will be conserved (the sum of momentum vectors is zero).
Random spinning orientations (I'll write this later)