Let's get this conundrum clear now. How do they behave in various setups. Our basic assumption is that these three free electrons are in equilateral triangle shape so that the distance between any two electrons is the same.

**1. Scenario**

All spinning vectors are parallel. The key player is the bottom electron which has FTEP flux which ejects FTEPs from underneath itself towards the other two (for more information check out subsection Two Electron Based Particles from Introduction to Theory of Everything by Illusion). This electron (electron B) starts to change its spinning vector orientation after the other two. But which one of these other two electrons starts the spinning orientation changing? Again, the surrounding FTE density dictates the order. The one which is closer to Earth's center of mass (electron C) generates denser FTEP flux (*), hence will be the anchor for the other electron. So, the spinning vector changing order would be, top electron, down electron and the original anchor electron. This order is also the order for electrons leaving the scene.

(*) If the triangle is top down, then the upper electron which ejects FTEPs from underneath of itself towards the other upper electron will be the anchor for the other upper electron. In the picture right it would electron A.

**2. Scenario**

There is two parallel spinning vectors (electrons A and B) and one antiparallel (electron C). This one is easy. Based on TL2 those antiparallel spinning vectors (B and C) generate repulsive force which triggers the movement for those electrons.

That single antiparallel electrons experiences the repulsion first and after that, electron A changes its spinning vector, which leads to repulsion between electrons A and B. At the same time electrons A and B are travelling away from electron C.

Again surrounding FTE ordered which electron changes its spinning vector orientation. Momentum will be conserved (the sum of momentum vectors is zero).

**3. Scenario**

Random spinning orientations (*I'll write this later*)